Let, Given number be n , count the number of digits present in this number
Example :
Input n= 9876
Output: 4
There are 4 digits in 9876 , which are 9 , 8 , 7 & 6.
Approach :
In this approach count the digits by removing the digits from the given number starting from right to left till the number is reduced to 0 . Here remove digits from right because rightmost digit can be removed by performing integer division by 10 . For eg : n=9876, then 9876/10 = 987.6=987(Integer Division ) .
import java.util.*;
public class CountDigits {
public static void main (String args[] ) {
Scanner sc = new Scanner ( System.in) ;
System.out.println(“Enter the number to count the digits in it”);
int num=sc.nextInt();
int temp=num,count=0;
// if the number is exactly 0 , it has 1 digit
if(temp==0) {
count=1 ;
} else {
//Loop runs until the number become 0
while (temp >0 ) {
temp=temp/10; //Removes the last digit
count++;
}
}
System.out.println(“Number of digits : ” + count);
}
}